fluent用LES算水翼边界层选择中心差分引起的震荡如何消除
-
李老师，可以先看下0.15弦长处的速度剖面，我是在这个位置插入一根沿z方向4mm线导出平均速度，x=0.0002m, y=-0.059182m, z=0.016964m到0.020964m，根据最大值无量纲化，图表附在文件里。velocity_profile_ldv_test_0.15C.zip
-
抱歉，李老师，那我直接把LDV的数据贴上吧，谢谢老师！
0.51874 0.02 0.54523 0.04 0.57821 0.06 0.60027 0.08 0.61619 0.1 0.63168 0.12 0.65259 0.16 0.67519 0.2 0.69035 0.24 0.71312 0.28 0.72578 0.32 0.75144 0.38 0.76757 0.42 0.78385 0.46 0.79825 0.5 0.81624 0.54 0.83174 0.58 0.86305 0.66 0.89698 0.74 0.9205 0.82 0.94188 0.9 0.96355 0.98 0.98842 1.14 0.99863 1.3 1.00000 1.46 0.99797 1.62 0.99706 1.78
-
- is it time-averaged U predicted by LES?
- What is the maxima? the Umax in this line or in the computational domain?
Your results look quite good. Is it predicted by linear scheme? How about the other schemes, e.g., limited schemes?
I am runing LES simulation, but it is very slow. I try to limit Co under 0.6. Since the global Umax is around 10 m/s, it indicates $\Delta t = 2.6e-6$. What value is your global Umax?
Courant Number mean: 0.00518159 max: 0.59921 deltaT = 2.67779e-06 Time = 0.0168822 GAMG: Solving for p, Initial residual = 0.0474207, Final residual = 0.00156874, No Iterations 2 time step continuity errors : sum local = 3.90116e-10, global = -6.12223e-14, cumulative = 5.73243e-11 DICPCG: Solving for p, Initial residual = 0.0105353, Final residual = 9.99036e-07, No Iterations 608 time step continuity errors : sum local = 2.48515e-13, global = -3.59741e-15, cumulative = 5.73207e-11 ExecutionTime = 401.48 s ClockTime = 421 s fieldMinMax minMaxp write: min/max(mag(U)) = 0 10.5464 Courant Number mean: 0.0051816 max: 0.601813 deltaT = 2.61829e-06 Time = 0.0168848 GAMG: Solving for p, Initial residual = 0.0479045, Final residual = 0.00156265, No Iterations 2 time step continuity errors : sum local = 3.72593e-10, global = 2.37179e-14, cumulative = 5.73444e-11 DICPCG: Solving for p, Initial residual = 0.0102726, Final residual = 9.97099e-07, No Iterations 152 time step continuity errors : sum local = 2.38352e-13, global = 2.12724e-14, cumulative = 5.73657e-11 ExecutionTime = 402.54 s ClockTime = 423 s -
I did a rough calculation, my time step is 3.3e-6, Co = 0.6, my server takes 2 s to calculate one time step. If I want to calculate 0.5 s, it takes me $0.5/(3.3e-6)*2/3600/24=2.5$ days to run, which looks too long for me.
Another point we need to discuss is that, if Umax is 11 m/s, to ensure Co < 1, you should use similar time step like mine.
试了从1e-5到5e-5
No matter 1e-5 or 5e-5, the Co is larger than 1. Unless time step is smaller than 5e-6, Co is smaller than 1.
Meanwhile, I heard that commercial software can employ much larger Co number. Since the code is not public to the users, I dont understand why.
-
-
Yes. My OpenFOAM results show that oscillation occurs if linear scheme is used. Although this can be explained by theory, you know that. You can try other schemes like
superbeewhich is quite sharp to verify if it predicts better results.Now, I terminate my calculation.
-
Below is the plot predicted by steadyState solver
simpleFoam. 10 mins is enough if you have 60/80 cores. You can see that it can be improved. I am not sure if LES can predict better results. Here is the test case, feel free to adjust the settings to see if you can obtain better results. Please also keep me updated. This is an excellent test case to investigate.
您有时间的话可以试试foam的中心差分格式，我用CFX和fluent都会有震荡。这是约450万的网格文件：
感兴趣的可以搞搞