return
neg(Re - 1000)*24*(1.0 + 0.15*pow(Re, 0.687))
+ pos0(Re - 1000)*0.44*max(Re, residualRe_);
https://www.openfoam.com/documentation/guides/v2206/api/reactingEuler_2multiphaseSystem_2interfacialModels_2dragModels_2SchillerNaumann_2SchillerNaumann_8C_source.html
结合SchillerNaumann阻力模型的公式,你看一下,公式我笔记里面有